WebFeb 19, 2024 · Trouver p sachant que A(5;22) appartient à la courbe de f The first three terms of a sequence are given. Round to the nearest thousandth ( if necessary) 12, 36, 108 Find the 9th term Weba. Evaluate the integral ∫ (4x2 + 2x -1) / (x3 +x2) dx b. Evaluate the integral ∫ x3 / 4 (4+x2)1/2. Given ∫ (x5−3x4+6x3+3)dx, evaluate the indefinite integral. Do not include +C in your answer. (a) Write out the MacLaurin polynomial of …
Math Calculator - Mathway Algebra Problem Solver
Web13. what is the intercept form of 15 x + 5y = -35 x=2 and y=1. Step-by-step explanation: (15×2)+(5×1)=35. 30+5=35. Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable. Exact Form: y = −. 7. 15. Decimal Form: y = −. 0.4 ¯ 6. 14. 15 × 8 +35÷5= 129 X[tex]15 \times 8 + 35 \div 5 ... Web22. Evaluate the polynomial x + x2 + x + 3 if the value of x = -2. A. 3 B.-3 C.17 D.-17 23. 3. Which of the following is equal to (x + 4) (x - 5) + 3 = 0?* 1 point A. x2 – x –17 = 0 B. x2 + x –17 = 0 C. x2 – x +17 = 0 D. x2 + x +17 = 0 24. 3. (x -- 4)(x + 5) = 3 A. *2 + x + 23 = 0 B.x2 + x -23 = 0 C. x2 - x + 17 = 0 D.x2-x + 17 = 0 fallout 76 hunting rifle vs lever action
Topic 3 Lesson 3-5 Evaluating Algebraic Expressions Flashcards
Web8. Evaluate the product of (x²-6xy+y²) and (x+y), when x=1 y=2 a. 21 b. -21 c. 1 d. -1 ... x−1 x+1. = ∞. 2. All the vertical asymptotes of the function f(x) = x2 − 1 x3 − 9x are at. ... Multiplication and Division of Integers 1. 3 x - 21 x 4 = 2. -7 x - 15 = 3. 1 216 / 2 = 4. -9 x (32 / -8) = 5. {-21 / (-3)} x - 4 = 1. -81 2. -8 3. -2 ... WebMar 4, 2024 · Solution. Following “Tips for Evaluating Algebraic Expressions,” first replace all occurrences of variables in the expression ( a − b) 2 with open parentheses. (a − b)2 = (() − ())2. Secondly, replace each variable with its given value, and thirdly, follow the “Rules Guiding Order of Operations” to evaluate the resulting expression. WebMar 3, 2016 · Let's first evaluate the integral as is: I = ∫ − 2 2 d y ∫ − 4 − y 2 4 − y 2 d x x ∫ x 2 + y 2 2 d z z = ∫ − 2 2 d y ∫ − 4 − y 2 4 − y 2 d x x ( 2 − x 2 − y 2) = 0. because we are integrating an odd function over a symmetric interval. Now let's try this in polar coordinates: I = ∫ 0 2 π d θ cos θ ⏟ =0 ∫ 0 ... convert 2048 to binary